How many digits are in a number n bits expressed in base b?
digits = n / (n / logb(2 ^ n))
In case your calculator doesn’t have a logb(n) function on it (mine doesn’t), use the version below.
digits = n / (n / (log(2 ^ n) / log(b)))
I’ve needed to know that several times and never took the time to figure it out or find it, but today I did. Isn’t that handy?